Collision Theory of Chemical Reactions
The Arrhenius equation explains the effect of temperature on the rate constant of a chemical reaction but does…
A first-order reaction is a chemical reaction in which the rate of reaction is directly proportional to the first power of the concentration of a single reactant. In other words, as the concentration of the reactant decreases, the reaction rate decreases proportionally. First-order reactions are among the most common reactions in chemistry and are widely encountered in radioactive decay, decomposition reactions, hydrolysis reactions, and pharmaceutical degradation. One of the most important characteristics of a first-order reaction is that its half-life is independent of the initial concentration of the reactant.
For a first-order reaction,
$$
A \longrightarrow \text{Products}
$$
the rate law is
$$
-\frac{d[A]}{dt}=k[A]
$$
where \(k\) is the first-order rate constant.
Starting from the differential rate equation,
$$
-\frac{d[A]}{dt}=k[A]
$$
Rearranging,
$$
\frac{d[A]}{[A]}=-k\,dt
$$
Integrating both sides between the limits:
$$
\int_{[A]_0}^{[A]}\frac{d[A]}{[A]}
=
-k\int_0^t dt
$$
$$
\ln[A]-\ln[A]_0=-kt
$$
$$
\ln\left(\frac{[A]}{[A]_0}\right)=-kt
$$
or,
$$
\ln\left(\frac{[A]_0}{[A]}\right)=kt
$$
Converting the natural logarithm into the common logarithm,
$$
\boxed{
k=\frac{2.303}{t}\log\left(\frac{[A]_0}{[A]}\right)
}
$$
This equation is known as the integrated rate equation for a first-order reaction.
A plot of \(\ln[A]\) versus time gives a straight line with a slope of \(-k\) and an intercept of \(\ln[A]_0\). Similarly, a plot of \(\log[A]\) versus time also gives a straight line with a slope of \(-k/2.303\).
$$
\text{Slope}=-k
$$
For a first-order reaction,
$$
k=\frac{1}{t}
$$
Hence, the SI unit of the first-order rate constant is
$$
\boxed{\mathrm{s^{-1}}}
$$
The half-life of a reaction is the time required for the concentration of the reactant to decrease to one-half of its initial value. For a first-order reaction, the half-life is constant and does not depend on the initial concentration of the reactant.
Using the integrated rate equation,
$$
k=\frac{2.303}{t}\log\left(\frac{[A]_0}{[A]}\right)
$$
At half-life,
$$
[A]=\frac{[A]_0}{2}
$$
Substituting,
$$
k=\frac{2.303}{t_{1/2}}
\log\left(\frac{[A]_0}{[A]_0/2}\right)
$$
$$
k=\frac{2.303}{t_{1/2}}\log2
$$
Since
$$
\log2=0.3010
$$
$$
k=\frac{2.303\times0.3010}{t_{1/2}}
$$
$$
k=\frac{0.693}{t_{1/2}}
$$
Therefore,
$$
\boxed{t_{1/2}=\frac{0.693}{k}}
$$
This equation shows that the half-life of a first-order reaction is independent of the initial concentration.
The mean life of a first-order reaction is the average lifetime of a reactant molecule before it undergoes a chemical change. It is represented by the symbol \(\tau\).
The mean life is related to the rate constant by
$$
\boxed{\tau=\frac{1}{k}}
$$
Since
$$
t_{1/2}=\frac{0.693}{k}
$$
therefore,
$$
\boxed{\tau=1.443\,t_{1/2}}
$$
Thus, the mean life of a first-order reaction is approximately 1.443 times its half-life.
More notes from the same unit.
The Arrhenius equation explains the effect of temperature on the rate constant of a chemical reaction but does…
The experimental observation that the rate of a chemical reaction increases with temperature raised an important question: Why…
Among all the factors that influence the speed of a chemical reaction, temperature has the most pronounced effect.…
The Isolation Method, also known as the Ostwald Method, is an experimental method used to determine the order…