Collision Theory of Chemical Reactions
The Arrhenius equation explains the effect of temperature on the rate constant of a chemical reaction but does…
A zero-order reaction is a chemical reaction in which the rate of reaction is independent of the concentration of the reactant. This means that changing the concentration of the reactant does not affect the reaction rate, provided that other conditions remain constant. Such reactions generally occur when the surface of a catalyst becomes completely saturated with reactant molecules or when the reactant is supplied at a constant rate. In a zero-order reaction, the reaction proceeds at a constant rate until the reactant is nearly exhausted.
For a zero-order reaction,
$$
A \longrightarrow \text{Products}
$$
the rate law is
$$
-\frac{d[A]}{dt}=k
$$
where \(k\) is the zero-order rate constant.
Starting from the differential rate equation,
$$
-\frac{d[A]}{dt}=k
$$
Rearranging,
$$
d[A]=-k\,dt
$$
Integrating between the limits:
$$
\int_{[A]_0}^{[A]} d[A]
=
-k\int_{0}^{t} dt
$$
$$
[A]-[A]_0=-kt
$$
or,
$$
[A]=[A]_0-kt
$$
This equation is known as the integrated rate equation for a zero-order reaction. It shows that the concentration of the reactant decreases linearly with time.
A plot of reactant concentration \([A]\) versus time \(t\) gives a straight line with a negative slope equal to \(-k\) and an intercept equal to the initial concentration \([A]_0\).
$$
\text{Slope}=-k
$$
$$
\text{Intercept}=[A]_0
$$
Since
$$
k=\frac{\text{concentration}}{\text{time}}
$$
the SI unit of the zero-order rate constant is
$$
\mathrm{mol\,L^{-1}\,s^{-1}}
$$
The half-life of a reaction is the time required for the concentration of a reactant to decrease to one-half of its initial value. It is denoted by \(t_{1/2}\). In a zero-order reaction, the half-life depends directly on the initial concentration of the reactant. Therefore, unlike a first-order reaction, the half-life of a zero-order reaction is not constant and decreases as the reaction proceeds.
The integrated rate equation for a zero-order reaction is
$$
[A]=[A]_0-kt
$$
At half-life,
$$
[A]=\frac{[A]_0}{2}
$$
Substituting this value into the integrated rate equation,
$$
\frac{[A]_0}{2}=[A]_0-kt_{1/2}
$$
Rearranging,
$$
kt_{1/2}=[A]_0-\frac{[A]_0}{2}
$$
$$
kt_{1/2}=\frac{[A]_0}{2}
$$
Therefore,
$$
\boxed{t_{1/2}=\frac{[A]_0}{2k}}
$$
The concept of mean life is generally not applicable to zero-order reactions. Mean life is derived from exponential decay and is therefore defined only for first-order reactions. Since the concentration of a reactant in a zero-order reaction decreases linearly with time rather than exponentially, there is no fixed expression for its mean life.
For examination purposes, remember that mean life is defined only for first-order reactions. It is not defined for zero-order or second-order reactions.
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